How many total atoms are in 0.530 g of p2o5/12131141/dc2696ff? utm_source=registration

In order to calculate the number of atoms present in 0.53 grams of P₂O₅, first calculate the number of moles for given mass.

As, Moles is given as,

                             Moles  =  Mass / M.mass

                             Moles  =  0.53 g ÷ 283.88 g.mol⁻¹

                             Moles  =  0.00186 moles

Now calculate the number of Molecules present in calculated moles of P₂O₅.

As,
                        1 Mole of P₂O₅ contains  =  6.022 × 10²³ Molecules
So,
             0.00186 Moles of P₂O₅ contain  =  X Molecules

Solving for X,
                        X  =  (0.00186 mol × 6.022 × 10²³ Molecules) ÷ 1 mol

                        X  =  1.12 × 10²¹ Molecules

Also, in P₂O₅ there are 7 atoms, in 1.12 × 10²¹ Molecules there will be

                            = 1.12 × 10²¹ × 7

                            =  7.84 × 10²¹ Atoms
Result:
            7.84 × 10²¹ Atoms are present in 0.53 grams of P₂O₅.

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