How many liters of .100 m hcl hcl would be required to react with 5 grams of calcium hydroxide?

The  number  of liters  of  0.100 HCl that would  be required  to  react with  5g of Ca(OH)2 is calculated  as  follows

find the   moles of Ca(OH)2  used

= mass/molar mas
=  5g/ 74.09 g/mol  = 0.0675  moles
write the  equation  involved

that is Ca(OH)2 +2 HCl = CaCl2 + 2 H2O

by use of mole ratio  between  Ca(OH)2  to HCl  which  is 1:2  the  moles  of  HCl  is therefore = 2 x 0.0675 = 0.135  moles  of HCl

volume of HCl =  moles of HCL / molarity of HCl

= 0.135/ 0.100 = 1.35 L

Just took the quiz on edgenuity and the correct answer is "c.  4.54 x  10–12  j"