According to the balanced chemical equation, how many atoms of silver will be produced from combining 100 g of copper with 200 g of silver nitrate?

The balance chemical equation is as follow,

                    Cu  +  2 AgNO₃    →    Cu(NO₃)₂  +  2 Ag

First calculate for 200 g of AgNO₃,
According to equation,

              339.74 g (2 mole) AgNO₃ produced  =  215.7 g (2 mole) of Ag
So,
                         200 g of AgNO₃ will produce  =  X g of Ag

Solving for X,
                              X  =  (200 g × 215.7 g) ÷ 339.74 g

                              X  =  126.97 g Ag

Next calculate for 100 g of Cu,
According to equation,

              63.52 g (1 mole) Cu produced  =  215.7 g (2 mole) of Ag
So,
                       100 g of Cu will produce  =  X g of Ag

Solving for X,
                              X  =  (100 g × 215.7 g) ÷ 63.52 g

                              X  =  339.57 g Ag
Result:
          As 200 g of AgNO₃ is producing Ag in less amount (126.97 g) as compared to 100 g of Cu, it means that AgNO₃ is in limited amount and will consume first till the production of 126.97 g of Ag. So, the maximum amount of Ag production is 126.97 g.

The answer is b because a,c,and d are opinons

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