Given the balanced ionic equation representing a reaction: 2al(s) + 3cu2+(aq) → 2al3+(aq) + 3cu(s)which half-reaction represents the reduction that occurs? al → al3+ +3eal3+ +3e → alcu→ cu2+ +2ecu2+ + 2e → cu

Option D :

Reduction take place when oxidation state of atom of an element decrease. Here, addition of electron/s takes place. Opposite to that in oxidation, oxidation state increases and here, loss of electron/s take place.

The balanced chemical equation is as follows:

Here, oxidation state of Al changes from zero to +3 thus, it undergoes oxidation and oxidation state of Cu changes from +2 to zero thus, it undergoes reduction.

The half reactions will be:

Oxidation:

Reduction:

Therefore, option D is correct.

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