M (using 98 points to post) given that the molal freezing point depression constant (kf) for methyl alcohol (ch3oh) is -0.83 oc/molal, how much will the freezing point of methyl alcohol be lowered if 46.0 g of glycerine (c3h8o3) is added to 1.00 kg of methyl alcohol? (must show work, correct unit and correct answer)

2.86 °C = (1) (1.86 °C kg mol-1) (x / 0.750 kg)

2.86 °C = (2.48 °C mol-1) (x)

x = 1.1532 mol

33.7 g / 1.1532 mol = 29.2 g/mol

the temperature of the gas, in k, not celsius.

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i think? ?