subject
Chemistry, 21.07.2019 15:30 mdegracia73

The formula for the illegal drug cocaine is c17h21no4 (303.39 g/mol). what is the percentage of hydrogen in the compound? 21.09% 4.618% 67.30% 6.991% 3.959%

ansver
Answers: 1

Another question on Chemistry

question
Chemistry, 22.06.2019 02:20
Calculate the molarity of 48.0 ml of 6.00 m h2so4 diluted to 0.250 l .
Answers: 1
question
Chemistry, 22.06.2019 06:00
Ethanol (c2h5oh) is produced from the fermentation of sucrose in the presence of enzymes. c12h22o11(aq) + h2o(g) 4 c2h5oh(l) + 4 co2(g) determine the theoretical yield and the percent yields of ethanol if 680. g sucrose undergoes fermentation and 326.5 g ethanol is obtained. theoretical _ g _ percent %
Answers: 1
question
Chemistry, 22.06.2019 19:50
If a gas has an initial pressure of 101kpa and a volume of 10l, then it expands to a volume of 20l, what is the new pressure?
Answers: 2
question
Chemistry, 22.06.2019 22:30
Draw the aromatic compound toluene (methylbenzene). show all hydrogen atoms, including those on the ring.
Answers: 1
You know the right answer?
The formula for the illegal drug cocaine is c17h21no4 (303.39 g/mol). what is the percentage of hydr...
Questions
question
World Languages, 26.06.2019 08:30
question
Mathematics, 26.06.2019 08:40
Questions on the website: 13722359