When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction caco3(s)→cao(s)+co2(g) what is the mass of calcium carbonate needed to produce 61.0 l of carbon dioxide at stp? express your answer with the appropriate units?

For producing 61 L of , 227.23 grams of  . is required.

Any gas occupies 22.4 L/mol space at STP.

So, 61.0 L of gas will be;

Moles of =

Moles of   = 2.723 moles

From the reaction,

1 mole of has been produced by 1 mole of .

2.723 moles of has been produced by 2.723 mole of .

Mass =

Mass of . = 2.723 100

Mass of . = 227.23 grams.

For producing 61 L of , 227.23 grams of  . is required.

For more information, refer the link:

link

they must be certified by the avma. ( a.)

mark me the branliest.

the answer is c

tell me if wrong