If 4.27 g sucrose (c12h22o11) are dissolved in 15.2 g water, what is the boiling point of the resulting solution? kb for water = 0.512c/m.

Answer : The boiling point of a solution is,

Explanation :

Formula used for Elevation in boiling point :

or,

where,

= boiling point of solution = ?

= boiling point of pure water =

= boiling point constant  for water =

m = molality

= mass of solute (sucrose) = 4.27 g

= mass of solvent (water) = 15.2 g

= molar mass of solute (sucrose) = 342.3 g/mole

Now put all the given values in the above formula, we get the boiling point of a solution.

Therefore, the boiling point of a solution is,

3

explanation:

the answer is c

tell me if wrong