What volume of 0.45 m lioh would be needed to neutralize 60.0 ml of 0.15 m hi?

Answer is: volume of 0.45 M LiOH is 20 mL.
Chemical reaction: LiOH + HI → LiI + H₂O.
From chemical reaction: n(LiOH) : n(HI) = 1 : 1.
c(LiOH) · V(LiOH) = c(HI) · V(HI).
0.45 M · V(LiOH) = 0.15 M · 60.0 mL.
V(LiOH) = 0.15 M · 60.0 mL / 0.45 M.
V(LiOH) = 20 mL ÷ 1000 mL/L = 0.02 L.
n - amount of the substance.
c - concentration of solution.

If the water vapor content stays the same and the temperature drops, then the relative humidity increases. its vise versa.if the water vapor content stats the same and the temperature rises, the relative humidity decreases. so, yes, i'd say that temperature and humidity have a strong relationship.