Complete the following table. acid molarity moles of h⁺ released per liter hcl 1 h2so4 1 h3po4 1 h2so4 0.5 h3po4 3 hno3 2

see the last column in the final table of the explanation below.

Explanation:

1) Arrange the data to understand the question:

Acid                 Molarity         Moles of H⁺ released per liter

HCl                      1                 

H2SO4                1                  

H3PO4                1                  

H2SO4                 0.5              

H3PO4                 3                  

HNO3                   2                 

2) All the given acids are strong acids, so you can consider they dissociate completely and release all the hydrogens present in the chemical formula.

3) The molarity formula is M = n/V, where n is the number of moles of solute and V is the volume of the solution in liters

From that, n = M×V

Go one by one with that formula.


Acid          Molarity    Moles of solute    number of H in            Moles H⁺                                  per liter                 the chemical formula  per liter

HCl            1             1M×1L = 1                  1                                  1×1 = 1

H₂SO4₄      1             1M×1L = 1                 2                                  2×1 = 2                 
H₃PO₄        1              1M×1L = 1                3                                 3×1 = 3

H₂SO₄         0.5           0.5M×1L = 0.5       2                                2×0.5 = 1

H₃PO₄        3               3M×1L = 3            3                                 3×3 = 9       
 
HNO₃         2               2M×1L = 2            2                                 2×2 = 4

The answer is celsius