The net ionic equation for the reaction between aqueous sulfuric acid and aqueous sodium hydroxide is a. h+ (aq) + hso4- (aq) + 2oh- (aq) → 2h2o (l) + so42- (aq) b. h+ (aq) + hso4- (aq) + 2na+ (aq) + 2oh- (aq) → 2h2o (l) + 2na+ (aq) + so42-(aq) c. so42- (aq) + 2na+ (aq) → 2na+ (aq) + so42-(aq) d. h+ (aq) + oh- (aq) → h2o( l) e.2h+ (aq) + so42- (aq) + 2na+ (aq) + 2oh- (aq) → 2h2o (l) + 2na+ (aq) + so42- (aq)

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.

i think is conclusions.i think so

i believe the answer is three water molecules