In the following three games, is each a coordination game or a prisoner's dilemma? the best way to check is to see if there is exactly one nash equilibrium; another way is to see if there is a dominant strategy for each player. to keep it a little challenging, we won't give the actions obvious labels that might give away the answer. higher numbers are always better.

What does a cascading style sheet resolve a conflict over rules for an element? a. the rule affecting the most content wins b. the rule affecting the most content loses c. the rule with the most specific selector loses d. the rule with the most specific selector wins

1. web and mobile applications allow users to be actively engaged in an online activity. a true b false 2. some examples of business applications purposes are to collaborate, share files, meet virtually in real-time, and accept payments. a true b false 3. an education application would most likely do which of the following? a allow users to watch popular movies and tv shows b connect users with social and business contacts c confirm users' travel plans d teach users a new language 4. a uniform resource locator (url) is how the internet knows where to take users when an address is typed into a browser. a true b false 5. deon is required to provide the citation information for his sources. what type of information should he collect from his sources? a author name, title, date of publication, date of access, url b connections to background information c interesting facts and statistics d notes on important information

Create a string list. 2. use console.readline() to collect values of firstname, lastname, street, city, state, zip, save them to list. 3. write a simple linq statement, call method uppercasewords() to change first letter to uppercase. 4. create a foreach statment to display the information. public static string uppercasewords(string value) { char[] array = value.tochararray(); if (array.length > = 1) { if (char.islower(array[0])) { array[0] = char.toupper(array[0]); } } for (int i = 1; i < array.length; i++) { if (array[i - 1] == ' ') { if (char.islower(array[i])) { array[i] = char.toupper(array[i]); } } } return new string(array);