Write a program which promptsuser to enter an integer value. using while loop print the valuesfrom
zero up to the number enteredby the user.
• enlist the odd numbers out of them
• enlist the prime numbers out of odd number list and printtheir sum (add all the prime numbers)

Following is the c++ code for the problem:

#include <iostream>

using namespace std;

int main() {

   int number;

   cout<<"Enter the number"<<endl;

   cin>>number;

   int i=0,c=0,odd[500];

   while(i<=number)//loop for printing the numbers form 0 to number.

   {

       cout<<i<<" ";

       if(i%2!=0)// storing in the odd array if the number is odd.

       {

           odd[c++]=i;//storing odd numbers..

       }

       i++;

   }

   cout<<endl;

   i=0;

   cout<<"The odd numbers are "<<endl;

   while(i<c)//loop to print the odd numbers.

   {

       cout<<odd[i]<<" ";

       i++;

   }

   cout<<endl<<"The prime numbers are "<<endl;

   i=0;

   int sum=0;

   while(i<c)//loop to print the prime numbers..

   {

       int div=2;

       while(div<odd[i])

       {

           if(odd[i]%div==0)

           break;

           div++;

       }

       if(div==odd[i])

      {

           cout<<odd[i]<<" ";

           sum+=odd[i];//updating the sum..

      }

       i++;

   }

   cout<<endl<<"The sum of odd prime numbers is "<<sum<<endl;//printing the sum..

return 0;

}

Output :

Enter the number

49

0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49  

The odd numbers are  

1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49  

The prime numbers are  

3 5 7 11 13 17 19 23 29 31 37 41 43 47  

The sum of odd prime numbers is 326 .

Explanation:

First I have printed the values from 0 to n and i have taken an array to store odd numbers.After that i have printed the odd values.And after that i have printed prime numbers among the odd numbers and their sum. These all operations are done using while loop.

the answer is d underlined.