What does the following statement do if usernumber has an integer value of 14 and userentry has a string value of “two”? usernumber = integer. parseint(userentry); a. throws an exception b. converts “two” to “2” and stores it in userentry c. converts “two” to 2 and stores it in usernumber d. stores a null value in usernumber

The correct answer for the given question is option(A) i.e  Throws an exception .

Explanation:

following are the code in java language

public class Main

{

 public static void main (String[]args)

 {

int userNumber =14;

String userEntry="two";

userNumber= Integer.parseInt(userEntry);

System.out.println(userNumber);

 }

}

The main class throws an  EXCEPTION  java.lang.NumberFormatException

because we cannot convert the string  userEntry into integer.

output

Exception in thread java.lang.NumberFormatException

so much for the extra points :

only #2 represents an object at rest on a table.

in #1, there is no normal force due to the table; the object is accelerating downward.

in #3, the vertical forces are not balanced; the object is accelerating downward.

in #4, neither the vertical nor the horizontal forces are balanced. the object is accelerating upwards and to the right.