)what item is at the front of the list after these statements are executed?
dequeinterface waitingline= new linkeddeque< > ();
waitingline. addtofront("jack");
waitingline. addtolback("rudy");
waitingline. addtoback("larry");
waitingline. addtolfront("sam");
name =getback();
waitingline. addtoback("adam");
a. sam b. adam. c. rudy. d. jack e. all other answers

Option (a) : sam

Explanation:

In the given program, the queue is defined in the first step.The method addToFront() adds the given element to the front of the queue. After this step is executed the front element in the queue is that element.The method addToBack() adds the given element to the back of the queue. After this step is executed the back element in the queue is that element.After step 1, Jack is added to the front of the queue.After step 2, Rudy is added to the back of the queue.After step 3, Larry is added to the back of the queue.After step 4, sam is added to the front of the queue.After step 5, name contains Larry as the getBack() returns the element present at the back of the queue.After step 6, Adam is added to the back of the queue.After executing all of the steps now the queue contains "sam" as the front element of the queue.So, the correct option is "sam".