The objective of this problem is to compare second-order accurate forward, backward, and centered finite-difference approximations of the first derivative of a function to the actual value of the derivative. this will be done for
f (x) = e−2x − x
(a) use calculus to determine the correct value of the de­rivative at x = 2.
(b) develop an m-file function to evaluate the centered finite-difference approximations, starting with x = 0.5. thus, for the first evaluation, the x values for the cen­tered difference approximation will be x = 2 ± 0.5 or x = 1.5 and 2.5. then, decrease in increments of 0.1 down to a minimum value of δx = 0.01.
(c) repeat part (b) for the second-order forward and back­ward differences. (note that these can be done at the same time that the centered difference is computed in the loop.)
(d) plot the results of (b) and (c) versus x. include the exact result on the plot for comparison.

Explain the circumstances for which the interquartile range is the preferred measure of dispersion. what is an advantage that the standard deviation has over the interquartile range? choose the correct answer below. a. the interquartile range is preferred when the distribution is symmetric. an advantage of the standard deviation is that it increases as the dispersion of the data increases. b. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation. c. the interquartile range is preferred when the distribution is symmetric. an advantage of the standard deviation is that it is resistant to extreme values. d. the interquartile range is preferred when the data are bell shaped. an advantage of the standard deviation is that it is resistant to extreme values. e. the interquartile range is preferred when the data are skewed or have outliers. an advantage of the standard deviation is that it uses all the observations in its computation. f. the interquartile range is preferred when the data are bell shaped. an advantage of the standard deviation is that it increases as the dispersion of the data increases.