You have a network with a subnet of 172.16.17.0/22. which of the following is a valid host address? a. 172.16.17.1 255.255.255.252b. 172.16.0.1 255.255.240.0c. 172.16.20.1 255.255.254.0d. 172.16.16.1 255.255.255.240e. 172.16.18.255 255.255.252.0f. 172.16.0.1 255.255.255.0

E. 172.16.18.255 255.255.252.0

Explanation:

Oh goodie, this is my home turf.

The answer is E) 172.16.18.255 255.255.252.0

This is because your subnet network ID includes mask \22, which means the ending with 255 255.255.252.0, which is standard for Class B. Only option E falls as an adequate host due to the network being 172.16.16 and broadcasting 16.19.

answers

a. nitrogen (n)

d. oxygen (o)

hope it