Using for loop . input an integer and identify whether it's even or odd ( without using modulo operator )
using only . c++ programming

Following are the program in c++ language

#include<iostream> // header file

using namespace std; // namespace

int main()  

{

int n1,i; // variable declaration

cout<<"Enter Number: ";

cin>>n1; // input number

for(i=n1;i>1;i=i-2) // check the condition  

{

n1 = n1-2; // decrement the value of number by -2  

}

if(n1==0) // check if it is 0

cout<<"number is EVEN"<<"\n"; // print even

else

cout<<"number is ODD"<<"\n"; // print odd

return 0;

}

Output:

Enter Number: 45

number is ODD

Again run the program

Enter Number:10

number is EVEN

Explanation:

In this program, we input the number by a user in variable n1. After that, we iterate the for loop and initialize the value of a variable" i" in for loop and check the condition.

In each iteration, the variable n1 is decrement by 2 and store it n1.

Finally, check if n1==0 then it print number is EVEN  otherwise it print number is ODD.

answergrowing self-confidence can give you a 'winning

the answer is b) 2nd

hope this and plz mark as brainliest!