For this question you should write code using the tools you learned so far. the code will find all the integers in the interval from 1 to 12000 that are divisible by both 3 and 14. print all the numbers that satisfy this criterion and also print a statement saying how many such number exist in the range. hint: the "modulo" operator is denoted by a percent sign % in python. it returns the remainder when two integers are divided. for example, 5%2 (read: "5 mod 2") returns a value of 1, because 5 divided by 2 is 2 with the remainder 1. the result of a modulo x%d is always between 0 and d-1. use the modulo operator to determine if one integer is divisible by another. second hint: remember the logical operators and, or and not are available in python.

The code in Python 3.7 than answers this question is given below:

def main():

 cont = 0

 for i in range(1, 12001):

   if i%3 == 0 and i%14 == 0:

     print(i)

     cont += 1

 print("{} numbers are divisible by 3 and 14".format(cont))

if __name__== "__main__":

 main()

Explanation:

#Create the main function, inside this is our logic to solve the problem

def main():  

#Define a cont variable that storage the amount of numbers that satisfy the condition given

 cont = 0  

 #For loop between 1 and 12000

 for i in range(1, 12001):

   #Use the mod function to know if is divisible by 3 and by 14

   if i%3 == 0 and i%14 == 0:

     #Print the number that satisfy the condition

     print(i)    

     #Refresh the cont variable if the condition is satisfied

     cont += 1

     #Print the output  

  print("{} numbers are divisible by 3 and 14".format(cont))

if __name__== "__main__":  

 #Run the main function

 main()  

they really not common the os x is just a better version of the os like in iphone theirs xr and their xs

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