Using karnaugh maps, simplify the following boolean function:

f(a, b,c, d) = a' b' c' + b' c d' + a' b c d' + a b' c'

F(a,b,c,d)=b'c' + a'cd' + ab'd'.

Explanation:

The image of the corresponding k-map is attached to this answer please refer it.By the sop given in the question the k-map is formed.There are 3 groups formed 1 group of four 1's and 2 groups of 2 1's.Hence there are three sop and the sop is reduced from the previous SOP.