Java question. this program currently fails to compile because the parameters cannot be automatically converted to double in the statement triplesum = item1 + item2 + item3; . because thetype is bound to the class number, the number class' doublevalue() method can be called to get the value of the parameters as a double value. modify tripleavg() method to use the doublevalue() method to convert each of the parameters to a double value before adding them. public class itemminimum {public staticdouble tripleavg(thetype item1, thetype item2, thetype item3) {double triplesum = 0.0; triplesum = item1 + item2 + item3; return triplesum / 3.0; } public static void main(string[] args) {integer intval1 = 55; integer intval2 = 99; integer intval3 = 66; double doubleval1 = 14.5; double doubleval2 = 12.3; double doubleval3 = 1.75; // try tripleavg method with integerssystem. out. println("items: " + intval1 + " " + intval2 + " " + intval3); system. out. println("avg: " + tripleavg(intval1, intval2, intval3) + "\n"); // try tripleavg method with doublessystem. out. println("items: " + doubleval1 + " " + doubleval2 + " " + doubleval3); system. out. println("avg: " + tripleavg(doubleval1, doubleval2, doubleval3) + "\n"); return; }}