Which one is not a correct encapsulation example?

select one or more:

a. from transport layer to network layer segments become packets

b. from network layer to datalink layer packets become frames

c. from physical layer to datalink layer bits become frames

d. from transport layer to application layer message become segment / user datagram

e. from application layer to transport layer message become segmet / user datagram

This program will store roster and rating information for a soccer team. coaches rate players during tryouts to ensure a balanced team. (1) prompt the user to input five pairs of numbers: a player's jersey number (0 - 99) and the player's rating (1 - 9). store the jersey numbers in one int vector and the ratings in another int vector. output these vectors (i.e., output the roster). (3 pts) ex: enter player 1's jersey number: 84 enter player 1's rating: 7 enter player 2's jersey number: 23 enter player 2's rating: 4 enter player 3's jersey number: 4 enter player 3's rating: 5 enter player 4's jersey number: 30 enter player 4's rating: 2

By refraining from constructing a building until they are certain that it will not cause harm to the environment, an organization is adhering to the

When making changes to optimize part of a processor, it is often the case that speeding up one type of instruction comes at the cost of slowing down something else. for example, if we put in a complicated fast floating-point unit, that takes space, and something might have to be moved farther away from the middle to accommodate it, adding an extra cycle in delay to reach that unit. the basic amdahl's law equation does not take into account this trade-off. a. if the new fast floating-point unit speeds up floating-point operations by, on average, 2ă—, and floating-point operations take 20% of the original program's execution time, what is the overall speedup (ignoring the penalty to any other instructions)? b. now assume that speeding up the floating-point unit slowed down data cache accesses, resulting in a 1.5ă— slowdown (or 2/3 speedup). data cache accesses consume 10% of the execution time. what is the overall speedup now? c. after implementing the new floating-point operations, what percentage of execution time is spent on floating-point operations? what percentage is spent on data cache accesses?