Write a function name isprime, which takes an integer as an argument and returns true if the argument is a prime number, or false otherwise. demonstrate the function in a complete program that reads in an integer that is less than 3001 stores a list of all the prime numbers from 2 through that number in a file named "primelist. txt" and to the standard output. screenshot: title, prompts, output, labels: program will write output to the file and to the standard output.1. a program writes the following text to the standard output(can bee seen in the top of the screen shot): cmsc 140 crn project 5: prime numbers2. after closing the file, the program writes to the standard output: a. on a line by itself : prime numbers are written to primelist. txtb. a list of primes input validation if the value read in exceeds 3000, the program writes on a line by itself in standard output: your input integer should be less than 3001. try again.

Program is given in C++, appropriate comments used

Explanation:

#include<iostream>

int isPrime(int n);

int main() //main function

{

int n, numPrime = 0;

FILE *fptr;

//create a empty file named "PrimeList.txt" at location where your program file is

fptr=(fopen("PrimeList.txt","w")); //open file in read mode

  if(fptr==NULL) //if file does not exist exit the program

  {

      printf("File does not exist \n");

      exit(1);

  }

for(n = 2; n<3001; n++)

{

  numPrime = isPrime(n);

  if(numPrime)

  {

      printf("%d is prime \n",n);

      fprintf(fptr,"%d \n",n);

  }

}

fclose(fptr);

return 0;

}

int isPrime(int n) //function to check prime number between 2-3001

{

  int flag = 0, i;

  for(i=2;i<=n/2;++i)

   {

     if(n%i==0)

     {

         flag=1;

         break;

     }

}

if (flag==0)

     return 1;

else

     return 0;

}

hey! im not 100 percent sure but im pretty sure that what you want to do is not possible : (

explanation: