Two users, usera and userb, are engaging in secure communication using only asymmetrical encryption. usera needs to send a secure message to userb. what occurs first? a. userb sends usera userb's public key
b. usera sends userb usera's private key
c. usera sends a secret key to userb

The correct answer is A: UserB sends UserA UserB's public key

Explanation:

In Asymmetrical Encryption, the both user involve in the secure communication must have a pair of key called public and private key. There are various step involves with engaging in Asymmetrical encryption, they include:

1. Each user generates a pair of keys to be used for the encryption and decryption of messages.

2. Each user places one of the two keys in a public register or other accessible file. This is the public key. The companion key is kept private.

3. If User B wishes to send a confidential message to User A, User B encrypts the message using User A's public key.

4. When User A receives the message, User A decrypts it using her private key. No other recipient can decrypt the message because only User A knows User A's private key.

Therefore, from the steps above, Option B and C are wrong because the private key/secret key should never be shared between users in asymmetrical encryption.

Option A is the correct answer as UserB sends UserA UserB's public key which is available to the everyone.

click the big logo on the top left of the screen.   hope this !

-ttl

solution:

this situation is called an ip conflict.

data from a server is sent in small bits called packets. in an ip conflict, some packets will end up in one computer while some other packets will end up in another computer.

so…overall none of the computers get the data as the original message or picture being sent by the server cannot be retrieved with only half the packets. so it will show up as an error.

thus the final answer is d.