Suppose that a selective-reject arq is used where w = 4. show, by example, that a 3-bit sequence number is needed.

Half of the window size is 2, so it count from 0 to 2;

- PC1 sends frames 0, 1, 2 to PC2.

- PC2 receives all three frames and tries to acknowledge with the third packet received.

3. Because of a noise burst, the acknowledgement for the third packet is lost.

4. PC1 times out and re-transmits the third packet.

5. PC2 has already increased its window size to accept frames 3, 0,

1, 2. Thus it assumes that frame 3 has been lost and that this is a

new frame 0, which it accepts.

Explanation:

The problem in this situation is that there is an increase from 2 to 3 bits between the sending and receiving windows. To resolve this issue, the range of sequence numbers should be more than half of the maximum window size  .  

yes the ansewer is c bc you can look it up!

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