In the following code, what is the first line that introduces a memory leak into the program?

(type the line number into the box below)

1: #include
2: #include
3: #include
4: int main() {
5: char *word1 = null;
6: word1 = malloc(sizeof(char) * 11);
7: word1 = "bramble";
8: char *word2 = null:
9: word2 = malloc(sizeof(char) * 11);
10: word2 = word1;
11: return 0;
12: }

The description of the given code is given below:

Explanation:

Memory leak:

In a program, if memory is assigned to the pointer variables but that memory is already released previously then the condition of occurring the memory leakage.

Now the program :

#include <stdio.h>  //header file

#include <stdlib.h>  //header file

#include <string.h> //header file

int main()   //main function

{

char *word1 = NULL;   //line 1 (as given in the question)

word1 = malloc(sizeof(char) * 11);  //line 2

free(word1);  //free the memory of pointer word1  line 3

word1 = "bramble";   //line 4

char *word2 = NULL;   //line 5

word2 = malloc(sizeof(char) * 11);   //line 6

free(word2);  //free the memory of pointer word2  line 7

word2 = word1;   //line 8

return 0;   //line 9

}

Therefore, line 3 is the first line that introduce a memory leak anf after that line 7 introduce it in a program.

answer ingenuity;