A tablet has a 7.5- × 5.8-inch screen size with a resolution of 326 pixels per inch. (a) How many pixels does it have? (b) With 256 levels of brightness for each color subpixel, what is the MiB size of the display memory?

13.2 miB

Explanation:

Total Number of pixels:

N = (326*7.5) * (326*5.8) = 4,623,006 pixels.

If we have 3 color subpixels, and any of them has 256 levels, this means that each color subpixel will have 8 bits.

⇒ 4,623,006*24*8 = 110,952,144 bits

As 1 byte = 8 bits,

N(Bytes) = 110,952,144 bits / 8 = 13,869, 018 bytes

As 1 MiB = 2²⁰ bytes = 1024*1024,

The total size of the display memory in MiBs is as follows:

N(MiB) =

⇒ N(MiB) = 13.2 MiB

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