Given numRows and numColumns, print a list of all seats in a theater. Rows are numbered, columns lettered, as in 1A or 3E. Print a space after each seat, including after the last. Ex: numRows = 2 and numColumns = 3 prints: 1A 1B 1C 2A 2B 2C

Step by step explanation along with code and output is provided below.

Explanation:

// the outer loop is for printing digits starting from 1 to numRows

// the inner loop is for printing letters starting from 'A' to numCols

//  char cols = 'A';   should not be inside inner loop or outside outer loop, in both these cases char either repeats itself or continues in a sequence. Therefore it must be inside of outer loop

//  int rows = 1;  ensures that row starts at 1

#include <iostream>

using namespace std;

int main()

{

int numRows;

int numCols;

int rows = 1;

cout <<"Enter number of Rows"<<endl;

cin>>numRows;

cout <<"Enter number of Columns"<<endl;

cin>>numCols;

cout<<"Seats in the theater are:"<<endl;

for(int i = 0; i < numRows; i++)

{

  char cols = 'A';  

 for(int j = 0; j < numCols; j++)

 {

 cout <<rows << cols << " ";

 cols= cols + 1;

 }

 rows= rows + 1;

}

  return 0;

}

Output:

When Rows = 2 and Columns = 3

Enter number of Rows

2

Enter number of Columns

3

Seats in the theater are:

1A 1B 1C 2A 2B 2C

When Rows = 4 and Columns = 5

Enter number of Rows

4

Enter number of Columns

5

Seats in the theater are:

1A 1B 1C 1D 1E 2A 2B 2C 2D 2E 3A 3B 3C 3D 3E 4A 4B 4C 4D 4E

Hence program is working correctly for any number of rows and columns

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