Write a JAVA program that, for four points A, B, C and P, which:a) Draws a triangle formed by ABC and a small cross showing the position of P. b) Displays a line of text indicating which of the following three cases applies:P liesO Inside ABCO Outside ABCO On an edge of ABC. The user will specify the four points by clicking. The same as part above, but, instead of displaying a line of text, the program computes the distances of P to the (infinite) lines AB, BC and CA, and draws the shortest possible line that connects P with the nearest of those three lines. The points can be specified by clicking. The program should be able to run on jGrasp.

The salespeople at hyperactive media sales all use laptop computers so they can take data with them on the road. you are a salesperson for superduper lightspeed computers talking to hyperactive media sales about upgrading the laptops to windows 10. explain how network location awareness in windows 10 would make the laptops more secure.

What is the main benefit of minimizing the ribbon in word? more options will be accessible through customized keystrokes. more of the document will be viewable without needing to scroll. fewer controls will be accessible to the user by using the mouse. fewer editing options will be available without entering a password.

Fill in the following program so that it will correctly calculate the price of the orange juice the user is buying based on the buy one get one sale.#include //main functionint main() { int cartons; float price, total; //prompt user for input information printf("what is the cost of one container of oj in dollars? \n"); scanf(" [ select ] ["%d", "%c", "%f", "%lf"] ", & price); printf("how many containers are you buying? \n"); scanf(" [ select ] ["%d", "%c", "%f", "%lf"] ", & cartons); if ( [ select ] ["cartons / 2", "cartons % 1", "cartons % 2", "cartons % price", "cartons / price", "cartons / total"] [ select ] ["=", "==", "! =", "< =", "> =", "< "] 0) total = [ select ] ["price * cartons", "cartons * price / 2 + price", "(cartons / 2) * price", "cartons / (2.0 * price)", "(cartons / 2.0) * price + price", "((cartons / 2) * price) + price"] ; else total = ((cartons / 2) * price) + price; printf("the total cost is $%.2f.\n", total); return 0; }