A ball is released from a 10 m high roof and bounces two thirds as high on each successive bounce. After traveling a total of 40 m (up and down motion), how many times did the ball bounce (e. g. touch the ground)? Put the answer in

Four times traveling 40,12345 mts

Explanation:

We can express this as a sum as follows

The first term is the dropping part and the second is the upward motion. this sums up to 40,12345 m after bouncing four times. As a program we could write using the while loop.

distance=0;

i:=0;

while distance<40 do

i:=i+1;

distance:=distance+

end while;

Here the answer is in i and the closest distance traveled after reaching 40 is in the variable distance.

1. a

2. a

3. d

explanation:

solution:

this situation is called an ip conflict.

data from a server is sent in small bits called packets. in an ip conflict, some packets will end up in one computer while some other packets will end up in another computer.

so…overall none of the computers get the data as the original message or picture being sent by the server cannot be retrieved with only half the packets. so it will show up as an error.

thus the final answer is d.