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G The machine in the problem has a byte-addressable memory of 216 bytes. The direct-mapped cache consists of 32 cache blocks, and the cache block size is 8 bytes. Question 1 How is the 16-bit memory address divided into byte offset, cache index, and tag? Question 2 What is the capacity of the cache in bytes? Question 3 Why tag is also stored in the cache? Question 4 For the following four memory addresses, what cache block would each be mapped to? 0001 0001 0001 1011 1100 0011 0011 0100 1101 0000 0001 1101 1010 1010 1010 1010
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G The machine in the problem has a byte-addressable memory of 216 bytes. The direct-mapped cache con...
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