Consider a point to point link 50 km in length. At what speed would propagation delay (at a speed 2 x 108 meters/second) equal transmit delay for 100 byte packets.

The bandwidth is 3200 Kbps

Explanation:

Given:

The length of the point to point link = 50 km = 50×10³ = 50000 m

Speed of transmission = 2 × 10⁸ m/s

Therefore the propagation delay is the ratio of the length of the link to speed of transmission

Therefore,  

Therefore the propagation delay in 25 ms

100 byte = (100 × 8) bits

Transmission delay =

If propagation delay is equal to transmission delay;

x = 3200 Kbps

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