Given a integer, convert to String, using String Builder class. No error checking needed on input integer, However do read in the input integer using Scanner API. This program requires you to use a loop.

The program in Java will be:

// Java program to demonstrate working parseInt()  

public class GFG  

{  

   public static void main(String args[])  

   {  

       int decimalExample = Integer.parseInt("20");  

       int signedPositiveExample = Integer.parseInt("+20");  

       int signedNegativeExample = Integer.parseInt("-20");  

       int radixExample = Integer.parseInt("20",16);  

       int stringExample = Integer.parseInt("geeks",29);  

       // Uncomment the following code to check  

       // NumberFormatException  

       //   String invalidArguments = "";  

       //   int emptyString = Integer.parseInt(invalidArguments);  

       //   int outOfRangeOfInteger = Integer.parseInt("geeksforgeeks",29);  

       //   int domainOfNumberSystem = Integer.parseInt("geeks",28);  

       System.out.println(decimalExample);  

       System.out.println(signedPositiveExample);  

       System.out.println(signedNegativeExample);  

       System.out.println(radixExample);  

       System.out.println(stringExample);  

   }  

}

answer; i believe that technician a is correct;

i don't know to be honest but you on your own

step-by-step explanation:

ignitia made me retarted fool im stoopid laugh like shi

explanation: