How do you do these two questions? The first might have multiple answers, the second has only one answer.

1. a) be relatively easy to calculate.

  b)map all the possible key values into the range of the valid hash table indices.

  c) returns smaller values more frequently than larger values.

2) number of entries required in a hash table = bucket size * load factor

                                = 120 *.75= 90

                               Each reference size =4 and we need not worry about the space taken by each object themselves.

        Hence, size = 90 x 4 =360 bytes.

Explanation:

Remember the hash functions must ensure ease in calculation. And the rest of the features are the salient feature of the hashset.

And Load factor = number of entries required in a hash table / bucket size.

the anwser is ethier d or e

solution:

this situation is called an ip conflict.

data from a server is sent in small bits called packets. in an ip conflict, some packets will end up in one computer while some other packets will end up in another computer.

so…overall none of the computers get the data as the original message or picture being sent by the server cannot be retrieved with only half the packets. so it will show up as an error.

thus the final answer is d.