subject

A more efficient version of the function for computing Tetranacci numbers can be defined by following three steps: 1. Implement a function which takes a list of integers and adds the sum of the top four elements to the head of the list (e. g., in F#, 1::1::1:1::/) should become 4:-1:-1::1::1::]). 2. Implement a recursive function which accepts an integer n as input (again, assumen > 0), and returns a list of integers from 0 to n in ascending order 3. Implement a recursive function which computes the nth Tetranacci number in linear time. This function may use a linear amount of space to compute its result, but the number of recursive calls it makes must be linear in n. Your task is to follow the three steps above, in order to implement the requested function in F#

ansver
Answers: 1

Another question on Computers and Technology

question
Computers and Technology, 23.06.2019 00:40
Consider the following statements: struct nametype{string first; string last; }; struct coursetype{string name; int callnum; int credits; char grade; }; struct studenttype{nametype name; double gpa; coursetype course; }; studenttype student; studenttype classlist[100]; coursetype course; nametype name; mark the following statements as valid or invalid. if a statement is invalid, explain why.a.) student.course.callnum = "csc230"; b.) cin > > student.name; c.) classlist[0] = name; d.) classlist[1].gpa = 3.45; e.) name = classlist[15].name; f.) student.name = name; g.) cout < < classlist[10] < < endl; h.) for (int j = 0; j < 100; j++)classlist[j].name = name; i.) classlist.course.credits = 3; j.) course = studenttype.course;
Answers: 1
question
Computers and Technology, 23.06.2019 13:00
Donnie does not have powerpoint. which method would be best for elana to save and share her presentation as is? a pdf a doc an rtf a ppt
Answers: 3
question
Computers and Technology, 24.06.2019 02:00
Write an expression that will cause the following code to print "equal" if the value of sensorreading is "close enough" to targetvalue. otherwise, print "not equal". ex: if targetvalue is 0.3333 and sensorreading is (1.0/3.0), output is:
Answers: 1
question
Computers and Technology, 24.06.2019 11:20
Print "censored" if userinput contains the word "darn", else print userinput. end with newline. ex: if userinput is "that darn cat.", then output is: censoredex: if userinput is "dang, that was scary! ", then output is: dang, that was scary! note: if the submitted code has an out-of-range access, the system will stop running the code after a few seconds, and report "program end never reached." the system doesn't print the test case that caused the reported message.#include #include using namespace std; int main() {string userinput; getline(cin, userinput); int ispresent = userinput.find("darn"); if (ispresent > 0){cout < < "censored" < < endl; /* your solution goes here */return 0; }
Answers: 3
You know the right answer?
A more efficient version of the function for computing Tetranacci numbers can be defined by followin...
Questions
question
History, 30.08.2019 02:00
Questions on the website: 13722359