A university has exactly one turnstile. It can be used either as an exit or an entrance. Unfortunately, sometimes many people want to pass through the turnstile and their directions can be different. The ith person comes to the turnstile at time[i] and wants to either exit the university if direction[i] = 1 or enter the university if direciton[i] = 0. People form 2 queues, one to exit and one to enter. They are ordered by the time when they came to the turnstile and, if the times are equal, by their indices.
If some person wants to enter the university and another person wants to leave the university at the same moment, there are three cases:

• If in the previous second the turnstile was not used (maybe it was used before, but not at the previous second), then the person who wants to leave goes first.

• If in the previous second the turnstile was used as an exit, then the person who
wants to leave goes first

• If in the previous second the turnstile was used as an entrance, then the person
who wants to enter goes first

Passing through the turnstile takes 1 second

For each person, find the time when they will pass through the turnstile

The function must return an array of n integers where the value at index[i] is the same when the ith person will pass the turnstile

The function has the following params:

• time: an array of n integers where the value at index i is the time when the
ith person will came to the turnstile
• direction: an array of n integers where the value at index i is the direction
of the ith person

Constraints

• 1 <= n <= 105
• 0 <= time[i] <= 109 for 0 <= i <= n – 1
• time[i] <= time[i+1] for 0 <= i <= n - 2
• 0 <= direction [i] <= 1 for 0 <= i <= n – 1

Example:

n = 4

time = [0,0,1,5]

direction = [0,1,1,0]

Output = [2,0,1,5]

Example 2

n = 5

time = [0,1,1,3,3]

direction = [0,1,0,0,1]

Output = [0,2,1,4,3]

Digital information is stored using a series of ones and zeros. computers are digital machines because they can only read information as on or off –1 or 0. this method of computation is known as the system

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Writing a modular program in visual c++. i am new to this and not sure what i am missing. i am getting the following error: baddate.cpp: in function ‘int main()’: baddate.cpp: 50: 3: error: ‘else’ without a previous ‘if’elsehere are the instructions and code: writing a modular program in c++in this lab, you add the input and output statements to a partially completed c++ program. when completed, the user should be able to enter a year, a month, and a day. the program then determines if the date is valid. valid years are those that are greater than 0, valid months include the values 1 through 12, and valid days include the values 1 through 31.notice that variables have been declared for you.write the simulated housekeeping() function that contains the prompts and input statements to retrieve a year, a month, and a day from the user.include the output statements in the simulated endofjob() function. the format of the output is as follows: month/day/year is a valid date.ormonth/day/year is an invalid date.execute the program entering the following date: month = 5, day = 32, year = 2014. record the output of this program.execute the program entering the following date: month = 9, day = 21, year = 2002. record the output of this /* program name: baddate.cppfunction: this program determines if a date entered by the user is valid.input: interactiveoutput: valid date is printed or user is alerted that an invalid date was entered*/#include bool validatedate(int, int, int); using namespace std; int main(){// declare variablesint year; int month; int day; const int min_year = 0, min_month = 1, max_month = 12, min_day = 1, max_day = 31; bool validdate = true; // this is the work of the housekeeping() method// get the year, then the month, then the daycout< < "enter the year"< > year; cout< < "enter the month"< > month; cout< < "enter the day"< > day; // this is the work of the detailloop() method// check to be sure date is validif(year < = min_year) // invalid yearvaliddate = false; else if (month < min_month || month > max_month) // invalid monthvaliddate = false; else if (day < min_day || day > max_day) // invalid dayvaliddate = false; // this is the work of the endofjob() method// test to see if date is valid and output date and whether it is valid or notif(validdate == true); {// output statementcout<