A lever has an effort arm that is 8 meters long and the resistance arm that is 1.5 meters long , how much effort is needed to lift a 200 newton weight ?

37.5N of effort is needed

Explanation:

Assuming efficiency of the machine is 100%

Efficiency = Work done by the load/Work done by the effort × 100%

100% = Work done by the load/Work done by the effort × 100%

1 = Work done by the load/Work done by the effort

Cross multiplying,

Work done by effort = Work done by Load

Note that work done = Force × distance

Work done by load = Weight × resistance arm

= 200×1.5

= 300Nm... 1

Work done by effort = Effort × effort arm

= 8 × Effort... 2

Equating 1 and 2, we have;

300 = 8×Effort

Effort = 300/8

Effort = 37.5N

37.5N

Explanation:

Step 1:

Data obtained from the question.

Effort arm length = 8m

Resistance arm length = 1.5m

Effort force =.?

Resistance force = 200N

Step 2:

Determination of the effort required to lift the 200N weight.

The effort required can be achieved by applying the following equation:

Effort force x Effort arm length = Resistance force x Resistance arm length

Effort force x 8 = 200 x 1.5

Divide both side by 8

Effort force = (200 x 1.5) /8

Effort force = 37.5N

Therefore, an effort of 37.5N is required to lift the 200N weight

the answer is gallery.