Mix ‘em Let s1 and s2 be 2 c-strings of the same length. Write a function char* mixem(char*s1, char* s2) which returns a c-string made up of the characters of s1 and s2 "interleaved", starting with the first character of s1. Example: S1="abc", s2="123" The call mixem(s1,s2) returns the c-string "a1b2c3" Note: If s is a c-string, strlen(s) returns the length of the string (not counting the terminating null character ‘\0’.) Every c-string has a null character at the end.

See Explaination

Explanation:

#include <iostream>

#include <string.h>

using namespace std;

char *mixem(char *s1, char *s2);

int main() {

cout << mixem("abc", "123") << endl;

cout << mixem("def", "456") << endl;

return 0;

}

char *mixem(char *s1, char *s2) {

char *result = new char[1 + strlen(s1) + strlen(s2)];

char *p1 = s1;

char *p2 = s2;

char *p = result;

while (*p1 || *p2) {

if (*p1) {

*p = *p1;

p1++;

p++;

}

if (*p2) {

*p = *p2;

p2++;

p++;

}

}

*p = '\0';

return result;

}

your game would probably crash if its too much lag but other players will also ! xd

hope this ! xd

also, can i get brainliest ?

solution:

the right option is a

to adding   a new row to a table we   have to do process last table cell and pressing tab.

this is the process to add new row in the cell:

* to add a row below the cell, click insert below in the rows and columns group.

thus this is the required right answer.