The variable grade can have any real number value from 0 to 100. Ask the user to enter a grade in numerical form. Write an if-elseif-else statement that displays the letter grade (any format) corresponding to a numerical grade in an appropriately formatted output statement. Use the standard 10-point grading scale: a: A: 90 ≤ grade a: B: 80 ≤ grade < 90 a: C: 70 ≤ grade < 80 a: D: 60 ≤ grade < 70 a: F: grade < 60

See explaination

Explanation:

#include <iostream>

using namespace std;

int main()

{

float marks;

cout<<"Enter your grade value :";

cin>>marks;

if(marks>=90)

cout<<"Your grade is 'A'";

else if(marks>=80&& marks<90)

cout<<"Your grade is 'B'";

else if(marks>=70&& marks <=80)

cout<<"Your grade is 'C'";

else if(marks>=60&& marks <70)

cout<<"Your grade is 'D'";

else

cout<<"Your grade is 'F'";

}

answer; its the top layer;

solution:

this situation is called an ip conflict.

data from a server is sent in small bits called packets. in an ip conflict, some packets will end up in one computer while some other packets will end up in another computer.

so…overall none of the computers get the data as the original message or picture being sent by the server cannot be retrieved with only half the packets. so it will show up as an error.

thus the final answer is d.