SUMMING THE TRIPLES OF THE EVEN INTEGERS FROM 2 THROUGH 10) Starting with a list containing 1 through 10, use filter, map and sum to calculate the total of the triples of the even integers from 2 through 10. Reimplement your code with list comprehensions rather than filter and map.

numbers=list(range(1,11)) #creating the list

even_numbers=list(filter(lambda x: x%2==0, numbers)) #filtering out the even numbers using filter()

triples=list(map(lambda x:x*3 ,even_numbers)) #calculating the triples of each even number using map

total_triples=sum(triples) #calculatting the sum

numbers=list(range(1,11)) #creating the list

even_numbers=[x for x in numbers if x%2==0] #filtering out the even numbers using list comprehension

triples=[x*3 for x in even_numbers] #calculating the triples of each even number using list comprehension

total_triples=sum(triples) #calculating the sum.

Explanation:

Go to the page where you are going to write the code, name the file as 1.py, and copy and paste the following code;

numbers=list(range(1,11)) #creating the list

even_numbers=list(filter(lambda x: x%2==0, numbers)) #filtering out the even numbers using filter()

triples=list(map(lambda x:x*3 ,even_numbers)) #calculating the triples of each even number using map

total_triples=sum(triples) #calculatting the sum

numbers=list(range(1,11)) #creating the list

even_numbers=[x for x in numbers if x%2==0] #filtering out the even numbers using list comprehension

triples=[x*3 for x in even_numbers] #calculating the triples of each even number using list comprehension

total_triples=sum(triples) #calculating the sum

answer; 5,000 to 100.000 typical is the minimum coverage,now every state is different;

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