For a surface to exist, it must have I closed-loop AND be coplanar.

True

False

False.

Explanation:

I will try to explain by presenting a contradiction to the given statement. Let us consider the surface of a sphere ( a ball is a sphere). While it has a closed loop surface it is not coplanar. In fact, a sphere exists in 3d and its surface can not lie in one plane. Hence, the given statement is false and surfaces do not have to be coplanar.

what is inputmismatchexception?

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