Write a recursive definition of x^n, where n≥0, similar to the recursive definition of the Fibonacci numbers. How does the recursion terminate?

Recursions are functions that execute itself from within.

The recursive definition x^n in Python, where comments are used to explain each line is as follows:

#This defines the function

def recursion(x, n):

   #This returns 1, if n is 0

   if(n==0):

       return 1

   #This calculates the power recursively, if otherwise

   else:

       return x*recursion(x,n-1);

The function terminates when the value of n is subtracted till 0

Read more about recursions at:

Following are the program to this question:

#include <iostream>//defining header file

using namespace std;

int recurs(int x, int n)//defining a method recurs that accepts two parameter

{

if(n==0)//defining if block that checks n value

{

return 1;//return value 1

}

else//defining else block

{

return x*recurs(x,n-1);//use return keyword that retun value

}

}

int main()//defining main method

{

cout<<recurs(5,3); //use print method to call recurs method

   return 0;

}

Output:

125

Explanation:

In the above-given program, the integer method "recurs" is declared which accepts, two integer variables, which are "x, n", inside the method the if conditional statement is used.

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