(The Location class) Design a class named Location for locating a maximal value and its location in a two-dimensional array. The class contains public data fields row, column, and maxValue that store the maximal value and its indices in a two dimensional array with row and column as int type and maxValue as double type. Write the following method that returns the location of the largest element in a two-dimensional array. public static int[] locateLargest(double[][] a)The return value is a one-dimensional array that contains two elements. These two elements indicate the row and column indices of the largest element in the two dimensional array. Write a test program that prompts the user to enter a two-dimensional array and displays the location of the largest element in the array. Here is a sample run:Enter the number of rows and columns of the array: 3 4Enter the array:23.5 35 2 104.5 3 45 3.535 44 5.5 9.6The location of the largest element is at (1, 2)

Here is the Location class:

public class Location {   //class name

   public int row;  // public data field to hold the value of no. of rows

   public int column;  // public data field to hold the value of no. of columns

   public double maxValue;   //public data field to hold the maximum value

   public Location(int row, int column, double maxValue) { //parameterized constructor of Location class

//this keyword is used to refer to a current instance variable and used to avoid naming conflicts between attributes and parameters with the same name

       this.row = row;  

       this.column = column;  

       this.maxValue = maxValue;     }  

   public static Location locateLargest(double[][] a) {   //method that takes a 2 dimensional array a as argument and returns the location of the largest element

       int row = 0;  //initializes row to 0

       int column = 0;  //initializes column to 0

       double maxValue = a[row][column];   //stores largest element

       for (int i = 0; i < a.length; i++) {  //iterates through rows of a[] array

           for (int j = 0; j < a[i].length; j++) {  //iterates through columns of array

               if (maxValue < a[i][j]) {  //if the maxValue is less than the element of 2 dimensional array at ith row and jth column

                   maxValue = a[i][j];  //then set that element to maxValue

                   row = i;  // i is set to traverse through rows

                   column = j;   }             }         }  // i is set to move through columns

       return new Location(row,column,maxValue);     }  } //calls constructor of class by passing row, column and maxValue as argument

Explanation:

Here is the Main class with a main() function to  test program  

import java.util.Scanner;   //to accept input from user

public class Main {   //class name

   public static void main(String[] args) {   //start of main function

       Scanner scan = new Scanner(System.in);  //creates Scanner class object to scan the input from user

 System.out.print("Enter the number of rows and columns in the array: ");  //prompt for user

       int row = scan.nextInt();  // reads value of row from user

       int column = scan.nextInt();  //reads input value of column

       double[][] array = new double[row][column];   //declares a 2 dimensional array named array

       System.out.println("Enter the array:");  //prompts to enter array elements

       for (int i = 0; i < array.length; i++) {  //iterates through the rows of array until the size of array is reaced

           for (int j = 0; j < array[i].length; j++) {  //iterates through the columns of array

               array[i][j] = scan.nextDouble();    }    }   //reads each element at i-th row and j-th column

       Location location = Location.locateLargest(array);  //calls locateLargest method by passing array to it in order to locate the largest element in the array

System.out.println("The largest element in a two-dimensional array is: " + location.maxValue);  //displays the largest element of array

       System.out.println("The location of the largest element is at (" + location.row + ", " + location.column + ")");       }    } //displays the location of the largest element in the two dimensional array

Suppose the user enters 2 rows and 2 columns. The elements are:

1         5.5

4.5      3

The program works as follows:

for (int i = 0; i < array.length; i++) this outer loop iterates through rows

i = 0

inner loop for (int j = 0; j < array[i].length; j++) iterates through columns

array[i][j] = scan.nextDouble(); reads the element at position i-th row and j-th column. This becomes:

array[0][0] = scan.nextDouble();

so element at 0th row and 0th column is 1

Location location = Location.locateLargest(array); now this calls the method which works as follows:

double maxValue = a[row][column]; this becomes:

double maxValue = a[0][0];

so maxValue = 1

for (int i = 0; i < a.length; i++) this loop in method iterates through rows and  for (int j = 0; j < a[i].length; j++) this iterates through columns of array

if (maxValue < a[i][j]) this becomes:

if (maxValue < a[0][0])

As we know that maxValue = 1 so this if condition is true.

                   maxValue = a[i][j];  this becomes:

             maxValue = a[0][0];  

maxValue = 1

Now set row = 0 and column = 0

Now the inner loop value of j is incremented to 1. So j = 1

At next iteration array[0][1] is checked. The element at this position is 5.5

if (maxValue < a[i][j]) is true because 1<5.5 so now value of maxValue becomes:

maxValue = 5.5

and

i = 0  j = 1

This way at each iteration of inner loop the columns are traversed and at each iteration of outer loop rows are traversed.

At next iteration element at array[1][0] is checked which is 4.5. This is not greater than maxValue so maxValue remains 5.5

At next iteration element at array[1][1] is checked which is 3. This is not greater than maxValue so maxValue remains 5.5 .

After both the loops end the statement:

return new Location(row,column,maxValue);

returns row , column and maxValue

where row = 0  column = 1 and maxValue = 5.5

So the output is:

The largest element in a two-dimensional array is: 5.5

The location of the largest element is at (0,1)

your game would probably crash if its too much lag but other players will also ! xd

hope this ! xd

also, can i get brainliest ?

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