What can an administrative account do that a regular user account cannot do

Assume that minutes is an int variable whose value is 0 or positive. write an expression whose value is "undercooked" or "soft-boiled" or "medium-boiled" or "hard-boiled" or "overcooked" based on the value of minutes. in particular: if the value of minutes is less than 2 the expression's value is "undercooked"; 2-4 would be a "soft-boiled", 5-7 would be "medium-boiled", 8-11 would be "hard-boiled" and 12 or more would be a "overcooked".

Could you find out how im still getting an 83 percent on this in edhesive a = input("enter an animal: ") s = input ("enter a sound: ") e = "e-i-e-i-o" print ("old macdonald had a farm, " + e) print ("and on his farm he had a " + a + "," + e) print ("with a " + s + "-" + s + " here and a " + s + "-" + s + " there") print ("here a " + s+ " there a " + s) print ("everywhere a " + s + "-" + s ) print ("old macdonald had a farm, " + e)

Print "censored" if userinput contains the word "darn", else print userinput. end with newline. ex: if userinput is "that darn cat.", then output is: censoredex: if userinput is "dang, that was scary! ", then output is: dang, that was scary! note: if the submitted code has an out-of-range access, the system will stop running the code after a few seconds, and report "program end never reached." the system doesn't print the test case that caused the reported message.#include #include using namespace std; int main() {string userinput; getline(cin, userinput); int ispresent = userinput.find("darn"); if (ispresent > 0){cout < < "censored" < < endl; /* your solution goes here */return 0; }