Define a function compute gas volume that returns the volume of a gas given parameters pressure, temperature, and moles. Use the gas equation PV nRT, where P is pressure in Pascals, V is volume in cubic meters, n is number of moles, R is the gas constant 8.3144621 (J/ (mol*K), and T is temperature in Kelvin. 1 gas. const -8.3144621 23 Your solution goes here 45 gas pressure 108.0 6 gas moles 1.0 7 gas .temperature-273. 8 gasvolume-.0 910 gasvolume compute. gasvolumeCgas pressure, gastemperature, gas moles) 11 printC' Gas volume:",gas volume, 'mA3)

Explanation:

import java.util.Scanner;

public class GasVolume {

final static double GAS_CONST = 8.3144621;

public static double computeGasVolume(double pressure,double temperature, double moles)

{

return moles*GAS_CONST*temperature/pressure;

}

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

double gasPressure = 0.0;

double gasMoles = 0.0;

double gasTemperature = 0.0;

double gasVolume = 0.0;

gasPressure = 100;

gasMoles = 1 ;

gasTemperature = 273;

gasVolume = computeGasVolume(gasPressure, gasTemperature, gasMoles);

System.out.println("Gas volume: " + gasVolume + " m^3");

return;

}

}

in python:

def gas_volume(pressure, temperature, moles)-> 'm^3':

   volume = (moles * 8.314462123 * temperature)/ pressure

   return volumn

Explanation:

The python program defines the function "gas_volume" that computes the volume of a gas when the gas pressure, number of moles, and the temperature is given. The result (which is the volume) is mapped to the documentation 'm^3' which is the unit of volume.

answer; i believe the above is false;