Write code which takes two inputs from the user, a number of sides followed by a side length, then creates a regular polygon with that number of sides and side length. Sample run:Type the number of sides:8Type a side length:7.5regular octagon with side length 7.5Hint: Make sure you use the right data types when taking user input.

import java.util.Scanner;

public class Polygon {

       public static void main(String[] args) {

               Scanner sc = new Scanner(System.in);

               System.out.println("Type the number of sides:");

               int sides = sc.nextInt();

               System.out.println("Type a side length:");

               double length = sc.nextDouble();

               if (sides== 5){

                      System.out.println("Pentagon, length "+length);

               } else if (sides == 6){

                      System.out.println("Hexagon, length "+length);

               } else if (sides == 7){

                      System.out.println("Heptagon length "+length);

               } else if (sides == 8){

                       System.out.println("Octagon, length "+length);

                } else if (sides == 9){

                       System.out.println("Nonagon, length "+length);

                 } else if (sides == 10){

                       System.out.println("Decagon, length "+length);

} else if (sides == 11){

                       System.out.println("Undecagon, length "+length);

} else if (sides == 12){

                       System.out.println("Dodecagon, length "+length);

} else {

                       System.out.println("Please choose a valid number.");

               }

       }

}

Explanation:

The Java source code defines a class called 'Polygon' the main method of the class prompts for user inputs for the sides and length variables. The nested if-statement prints the type of polygon with respect to the number of sides.

b. xor is the correct answer