A digital signaling system is required to operate at 9600 bps. a. If a signal element encodes a 4-bit word, what is the minimum required bandwidth of the channel

1200 Hz

Explanation:

Given that the signal encodes 4-bit words, then

log2M = 4,

Again, we're told that the system operates at 9600 bps, so

C = 9600

If we bring back our earlier relation, we have

9600 = 2B * 4

9600 = 8B

B = 9600 / 8

B = 1200 Hz

Therefore, we can conclude that the minimum required bandwidth of the channel is 1200 Hz

solution:

this situation is called an ip conflict.

data from a server is sent in small bits called packets. in an ip conflict, some packets will end up in one computer while some other packets will end up in another computer.

so…overall none of the computers get the data as the original message or picture being sent by the server cannot be retrieved with only half the packets. so it will show up as an error.

thus the final answer is d.