Computers and Technology, 25.01.2021 23:40 miamassimino
Consider the algorithm for the sorting problem that sorts an array by
counting, for each of its elements, the number of smaller elements and
then uses this information to put the element in its appropriate position
in the sorted array:
Algorithm ComparisonCountingSort(A[0..n β 1], S[0..n β 1])
//Sorts an array by comparison counting
//Input: Array A[0..n β 1] of orderable values
//Output: Array S[0..n β 1] of Aβs elements sorted in nondecreasing order
for i β 0 to n β 1 do
Count[i] β 0
for i β 0 to n β 2 do
for j β i + 1 to n β 1 do
if A[i] < A[j]
Count[j] β Count[j]+1
else Count[i] β Count[i]+1
for i β 0 to n β 1 do
S[Count[i]] β A[i]
a. Apply this algorithm to sorting the list 60, 35, 81, 98, 14, 47.
b. Is this algorithm stable?
c. Is it in place?
Answers: 2
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Computers and Technology, 23.06.2019 19:40
Use a physical stopwatch to record the length of time it takes to run the program. calculate the difference obtained by calls to the method system.currenttimemillis() just before the start of the algorithm and just after the end of the algorithm. calculate the difference obtained by calls to the method system.currenttimemillis() at the start of the program and at the end of the program so that the elapsed time includes the display of the result. use the value returned by the method system.currenttimemillis() just after the end of the algorithm as the elapsed time.
Answers: 3
Consider the algorithm for the sorting problem that sorts an array by
counting, for each of its ele...
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