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Computers and Technology, 27.01.2021 23:30 genyjoannerubiera
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Computers and Technology, 22.06.2019 12:00
The following function returns a string of length n whose characters are all 'x'. give the order of growth (as a function of n) of the running time. recall that concatenating two strings in java takes time proportional to the sum of their lengths. public static string f(int n) { if (n == 0) return ""; if (n == 1) return "x"; return f(n/2) + f(n - n/2); } options: a) constant b) logarithmic c) linear d) linearithmic e)quadratic f)cubic g) exponential
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Computers and Technology, 22.06.2019 21:30
This graph compares the total cost of attending educational institutions in texas. the graph demonstrates that the cost at private and public technical schools greatly varies.
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Computers and Technology, 23.06.2019 12:00
If you embed a word table into powerpoint, what happens when you make edits to the embedded data? a. edits made to embedded data change the data in the source file; however, edits made to the source file will not be reflected in the embedded data. b. edits made to embedded data will change the data in the source file, and edits made to the source file will be reflected in the embedded data. c. edits made to embedded data don't change the data in the source file, nor will edits made to the source file be reflected in the embedded data. d. edits made to embedded data don't change the data in the source file; however, edits made to the source file will be reflected in the embedded data.
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Computers and Technology, 23.06.2019 19:40
Use a physical stopwatch to record the length of time it takes to run the program. calculate the difference obtained by calls to the method system.currenttimemillis() just before the start of the algorithm and just after the end of the algorithm. calculate the difference obtained by calls to the method system.currenttimemillis() at the start of the program and at the end of the program so that the elapsed time includes the display of the result. use the value returned by the method system.currenttimemillis() just after the end of the algorithm as the elapsed time.
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