Write a recursive method called method3 that accepts an integer parameter and returns the integer reformed by repeating digits 1 and 2. For example, method3 (123456) will return 11223456 repeating only 1 and 2 and method3 (21) will return 2211. If the number is 0, return 0. You may assume that n is not negative

Explanation:

The following is written in Java and creates only the method3 and returns a new method after doubling all of the 2's and 1's in the input.

public static int method3(int x) {

       int finalValue = 0;

       String number = String.valueOf(x);

       for (int i = 0; i < number.length(); i++) {

           if (number.charAt(i) == 1 || number.charAt(i) == 2) {

               finalValue += Integer.valueOf(number.charAt(i));

               finalValue += Integer.valueOf(number.charAt(i));

           } else {

               finalValue += Integer.valueOf(number.charAt(i));

           }

       }

       return finalValue;

   }